Assume that when with smartphones are randomly selected, 46% use them in meetings or classes. If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

3.6%

Step-by-step explanation:

There is a 46% chance for someone to use the smartphone(A) and 54% that they didn't use the smartphone(B). The question of asking the probability that fewer than 3 of them use their smartphones. The calculation will be:

12C0 * A^12 * B^0       +    12C1 * A^11 * B^1       + 12C2 * A^10 * B^2

12C0 * 54%^12 * 46%^0       + 12C1 * 54%^11 * 46%^1      + 12C2 * 54%^10 * 46%^2       =

0.0006147876262 + 0.006284495734 + 0.02944402631

0.03634330967 = 3.6%

every 5 customers that walk in, only 2 buy popcorn.

step-by-step explanation:

basically 2/5.

brainliest would be appreciated.