The function f(x) is a cubic function and the zeros of f(x) are -6, -3 and 1. Assume the leading coefficient of f(x) is 1. Write the equation of the cubic polynomial in standard form.

f(x) = x³+8x²+9x-18

Step-by-step explanation:

Factors are: (x+6)(x+3)(x-1)

= (x+6)(x²+3x-x-3)

= (x+6)(x²+2x-3)

= x³+2x²-3x+6x²+12x-18

f(x) = x³+8x²+9x-18

Step-by-step explanation:

If is a zero of , then is a factor of .

Since -6,-3, and 1 are zeros, then we have the following factors of :

, , and .

Let's put it together.

, where is the leading coefficient and we are given to make it equal to 1, has zeros -6,-3, and 1.

We now need to put the factored form of into standard form by using multiplication and combining of like terms.

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )