I’m really stuck on this circle theorems question, can someone help please

Step-by-step explanation:

O is the center of the circle.  So OD, OC, and OB are all radii of the circle, and therefore congruent.

That means that ΔDCO and ΔCBO are isosceles triangles.  The base angles of isosceles triangles are congruent.  So ∠DCO = x.

ADP and ABQ are tangent to the circle.  Therefore, they are perpendicular to OD and OB.

Since ∠ABO = 90°, ∠CBO = 90° − 2x.  Which means ∠OCB = 90° − 2x.

∠BCD is the sum of ∠DCO and ∠OCB:

∠BCD = x + 90° − 2x

∠BCD = 90° − x

Angles of a triangle add up to 180°.  So:

∠DOC = 180° − x − x = 180° − 2x

∠BOC = 180° − (90° − 2x) − (90° − 2x) = 4x

Central angles add up to 360°.  So ∠DOB is:

∠DOB = 360° − (180° − 2x) − (4x)

∠DOB = 180° − 2x

The interior angles of kite ADOB add up to 360°.

360° = 90° + 90° + (180° − 2x) + y

360° = 360° − 2x + y

y = 2x

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

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