An animal shelter spends $5.50 per day to care for each cat and $8.00 per day to care for each dog. Owen noticed that the shelter spent $191.50 caring for cats and dogs on wednesday. How many cats were at the shelter on wednesday?

13, if 28 cats & dogs

Step-by-step explanation:

let c be the no. of cats and d be the no. of dogs

5.50c + 8d = 191.50

Notice that the sum is in 0.5, which is only possible when c is odd.

Try different combinations of c being odd and check which one gives d as a whole number, using

d = (191.50-5.50c)/8

c = 1, d = [191.50-5.50(1)]/8

d = 23.25 (not possible)

c = 3, d = [191.50-5.50(3)]/8

d = 21.875 (not possible)

c = 5, d = [191.50-5.50(5)]/8

d = 20.5 (not possible)

c = 7, d = [191.50-5.50(7)]/8

d = 19.125 (not possible)

c = 9, d = [191.50-5.50(9)]/8

d = 17.75 (not possible)

c = 11, d = [191.50-5.50(11)]/8

d = 16.375 (not possible)

c = 13, d = [191.50-5.50(13)]/8

d = 15 (possible)

So c = 13 and d = 15

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0