The sum of three numbers is 136. The second number is 10 more than the first. The third number is 4 times the first. What are the numbers?

The answer to your question is  21, 31, 84

Step-by-step explanation:

Data

sum = 136

1st = x

2nd = x + 10

3rd = 4x

Process

- Write an equation to find the numbers

                x + (x + 10) + 4x = 136

                x + x + 10 + 4x = 136

                6x = 136 - 10

                6x = 126

                  x = 126/6

                  x = 21

- Find the numbers

1sr number = 21

2nd number = 21 + 10 = 31

3rd number = 4(21) = 84

probability for j is 1/4

while

a is 1/6

correct answer is b. 27/8

step-by-step explanation: