A ball is tossed up vertically from ground level and returns to earth 6 s later. What was the initial velocity of the ball and how high did it go?

initial velocity = 29.4m/s

maximum height = 44.1m

Step-by-step explanation:

This problem is a projectile motion. The ball is tossed vertically from the ground, which means the angle between the ball and the horizontal is 90°

° (the ball is tossed vertically)

2Usinα = g*T

2U =gT/sinα

2U = 9.8* 6/ sin90°

2U=58.8

U = 58.8/2 =29.4

U=29.4m/s

maximum height attained (H) =

=

maximum height =44.1m

step-by-step explanation:

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