7 measured data points have a sample mean of 1403 and a standard deviation of 27. Determine the best estimate of the mean value at 95% probability level. Find a, where the best estimate of the mean value is expected to fall ±a about the sample mean.

Step-by-step explanation:

Hello!

You have sample of n=7 with mean X[bar]= 1403 and standard deviation S=27 and are required to estimate the mean with a 95%CI.

Asuming this sample comes from a normal population I'll use a stuent t to estimate the interval (a sample of 7 units is too small for the standard normal to be accurate for the estimation):

[X[bar]± * ]

[1403±2.365*]

[1378.87;1427.13]

The margin of error is the semiamplitude of the interval and you can calculate it as:

With a confidence level of 95% you'd expect that the real value of the mean is contained by the interval [1378.87;1427.13], the best estimate of the mean value is expected to be ± 24.13 of 1403.

I hope it helps!

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

step-by-step explanation:

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