A basketball player is fouled while attempting to make a basket and receives two free throws. The opposing coach believes there is a 55% chance that the player will miss both shots, a 25% chance that he will make one of the shots, and a 20% chance that he will make both shots. What is the probability that he makes no more than one of the shots? (Round your answer to 2 decimal places.)

0.8 = 80% probability that he makes no more than one of the shots

Step-by-step explanation:

We have these following probabilities:

55% probability that he misses both shots.

25% that he makes one of the shots

20% probability that he makes both shots.

What is the probability that he makes no more than one of the shots?

Sum of the probabilities of missing both or making one. So

55+25 = 80%

0.8 = 80% probability that he makes no more than one of the shots

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

its a trick question

step-by-step explanation:

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