Computer battery A has 4/5 of its power remaining. Computer battery B has 9/20 of its power remaining. How much more power does computer battery A have compared to computer battery B?

7/20

Step-by-step explanation:

GIven:

Battery A = 4/5 remaining

Battery B = 9/20 remaining

assuming both batteries are otherwise identical (except for charge level remaining), then,

Battery A - Battery B

= 4/5 - 9/20

we need to convert both fractions to same denominator to perform the subtraction easily. Note that the Least Common Multiple for 5 and 20 is 20, hence we convert both denominators to 20,

Battery A - Battery B

= 4/5 - 9/20

= (4/5) (4/4) - 9/20

= 16/20-9/20

= 7/20

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

      2

  2 is to go somewhat to the top right of a because it is squared    

v= a h/3