Given the first order IVP y′+6y={5x4e−6x,0,0≤x<1x≥1 with initial condition y(0)=2. (1) Find the explicit solution on the interval 0≤x<1 y(x)= e^(-6x)(x^5+2) . (2) Find the limx→1y(x)= 3e^-6 . (3) Then find the explicit solution on the interval x≥1 y(x)= 1+(3-e^6)e^(-6x) .

5

step-by-step explanation:

i believe it is d.) buddhism and e.) hinduism

3+3+3+2*2*2+29*12 = 365

step-by-step explanation:

assuming this is from a math graphing problem.

7 would be on the x-axis which is the horizontal line on the graph

84 would be on the y-axis which is the vertical line on the graph