From a circular card sheet of radius 28 cm, two circles of radii 7 cm each and a rectangle of length 3 cm and breadth 2 cm are removed. Find the area of the remaining sheets

2150cm^2

Step-by-step explanation:

In this question, there is a certain circular shape. Now, from this circular shape, 2 circles and 1 rectangle have been made. We are now asked to find the area of the remaining sheet.

Mathematically, the area of the remaining sheet is the area of the circular card sheet minus the area of the 2 circles and rectangle.

Now, we need to find the value of 3 areas I.e the areas of the circular sheet, the area of the circle(they are the same) and the area of the rectangle.

Mathematically, the area of a circle is

A = πr^2

For the whole circular sheet, the value of the radius is 28cm

A = 22/7 * 28 * 28 = 2464cm^2

The Area of the two circles made is

Mathematically, the area of a circle is

A = πr^2

Here, our r is 7cm

A = 22/7 * 7 * 7

A = 154cm^2

Since the circles are 2 in number, the total area here is thus 154 * 2 = 308cm^2

The area of the rectangle is L * B = 2cm * 3cm = 6cm^2

The area of the remaining part of the circular card sheet is: 2464 - 308 - 6 = 2150cm^2

answer: the common difference is -0.10