What are the values of a, and r of the geometric series?
1+3+9+ 27 + 81
0 2 = 1 and ra
0 a, - and r-1
O Q4 - 1 and r-3
O
a. - 3 and r - 1

Step-by-step explanation:

First term a = 1

common ratio r = 3/1=9/3=27/9=81/27 = 3

Hence,

a = 1 & r = 3

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.