The proof that AMNS AQNS is shown.
Given: AMNQ is isosceles with base MQ, and NR and MQ
bisect each other at S.
Prove: AMNS MAQNS
We know that AMNQ is isosceles with base MQ. So,
MN - QN by the definition of isosceles triangle. The base
angles of the isosceles triangle, ZNMS and ZNOS, are
congruent by the isosceles triangle theorem. It is also given
that NR and MQ bisect each other at S. Segments
are therefore congruent by the definition of bisector. Thus,
AMNS SAQNS by SAS.
Nc
NS and QS
NS and RS
MS and RS
MS and QS
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80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

33/100 is what i got

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14