The proportion of households in a region that do some or all of their banking on the Internet is 0.41. In a random sample of 1000 households from this region, let x be the number that do some or all of their banking on the Internet a. Find the mean of x

Step-by-step explanation:Hello!

X: number of households in a region that do some or all of their banking on the internet.

The proportion of households is p=0.41

n= 1000

For this variable there are two possible outcomes, the household either "does some or all baking online" (success) or "does no make banking online" (failure).

The number of repetitions is fixed n= 1000 households.

Assuming each household is independent of the others and the probability of success p=0.41 is the same for all households, then:

X~Bi(n;p)

The mean for a variable with binomial distribution is:

E(X)= n*p= 1000*0.41= 410

The expected value of households that do some or all banking online is 410.

I hope it helps!

step-by-step explanation:

no, her answer is not correct.   we square the lengths of all sides and then determine whether the pythagorean theorem holds here:

9² + 15² = 306.   this is not equal to the square of the longest side ( that square being 395.   answer c is correct.

answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil