Solve Ax=b by finding coefficients for the columns of A which show b lies in their span. When solving Ax=b the solution x can be determined by determining the linear combination of the columns of A which equal b. In the interactive cell below A1 represents the first column of A, A2 represents the second column of A and A3 represents the third column of A. Determine values of x1, x2 and x3 so that x1A1+x2A2+x3A3=b .

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step-by-step explanation:

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

the transitive property of equality.

step-by-step explanation:

the correct answer is:

the transitive property of equality.

explanation:

we know that  ∠bcd is congruent to  ∠pbc. we also know that  ∠pbc is congruent to  ∠bad.

we can substitute  ∠bad for  ∠pbc in the first angle congruence statement to give us:

∠bcd is congruent to  ∠bad.

algebraically, the transitive property states if a=b and b=c, then a=c. it basically allows us to substitute equal values. since that is what we did, this is the transitive property.

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step-by-step explanation: