Consider randomly selecting a single individual and having that person test drive 3 different vehicles. define events a1, a2, and a3 by a1 = likes vehicle #1 a2 = likes vehicle #2 a3 = likes vehicle #3. suppose that p(a1) = 0.55, p(a2) = 0.75, p(a3) = 0.70, p(a1 ∪ a2) = 0.90, p(a2 ∩ a3) = 0.30, and p(a1 ∪ a2 ∪ a3) = 0.84. -g

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

sorry i need the points

step-by-step explanation:

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uygybg bsyvyuenrs

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y6fy

the answer is a.

step-by-step explanation:

in three games of golf, alex shot two under par four times.