Suppose that distinct integer values are written on each of 3 cards. These cards are then randomly given the designations A, B, and C. The values on cards A and B are then compared.
1. If the smaller of these values is then compared with the value on card C, what is the probability that it is also smaller than the value on card C?

2/3

Step-by-step explanation:

The possible outcome from the three designations is express as 3!

and 3!=3x2x1=6

Hence the 6 possible outcome are listed below

(A,B,C),(A,C,B),(B,A,C),(B,C,A),(C,A,B) and (C,B,A)

let assume A should be less than B and B less than C, i.e A<B<C

The question required us to solve for

P(min(A,B)<C). And this can be expressed as

P(min(A,B)<C)=P(A<C)+P(B<C)-P(AB<C).

From the order given above, there are 3 possible outcome for A to come before C

Hence P(A<C)=3/6=1/2

also there 3 possible outcome for B to come first before C

P(B<C)=3/6=1/2

Also, there 2 events for A,B to come before C

P(AB<C)=2/6=1/3

Hence in final

P(min(A,B)<C)=P(A<C)+P(B<C)-P(AB<C)=1/2+1/2-1/3=2/3

the probability that it is also smaller than the value on card C is 2/3

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d