Find the second derivative at the point (1,1), given the function below. 2x^9+1=3y^3

The value at point ( 1, 1 ) is 8.

Explanation:

Given

3y³ = 2x⁹ + 1

y³ = 2/3x⁹ + 1/3

y = ∛2/3 x⁹ + 1/3

We need to first find dy/dx which is the first derivative and then d²y/dx² which is the second derivative

Put the value of (1,1) : x = 1 and y = 1 in d²y/dx² equation

Therefore, the value is 8.