The slope-intercept form of the equation of a line that passes through point (–2, –13) is y = 5x – 3. what is the point-slope form of the equation for this line?
y – 13 = 5(x – 2)
y + 13 = 5(x + 2)
y – 2 = 5(x – 13)
y + 2 = 5(x + 13)

The point slope form of the equation of the line is generally expressed as, 
                                       y - y1 = m(x - x1)
where m is the slope, x1 and y1 are the abscissa and ordinate of the given point. The slope of the line is given to be 5. Therefore, the equation of the line is,
                                    y + 13 = 5(x +2)
This is the second choice. 

Idon’t actually know but have you asked google yet