What is the probability that a simple random sample of 60 unemployed individuals will provide a sample mean within 1 week of the population mean? (Round your answer to four decimal places.)

The question is not complete so I will answer it with an example and a few assumptions. Follow the steps to find the answer to your question.

Important to note:

Your question is a z-scores problem

Assume that for the population of unemployed individuals the population standard deviation is 4 weeks.

Thus, we need to find the z-value.

The z-value is the sample mean decreased by the population mean, divided by the standard deviation that we assumed. So, we have:

Using any standard negative z-scores table, we can find that:

Thus, we get:

Therefore, the probability that a simple random sample of 60 unemployed individuals will provide a sample mean within 1 week of the population mean is 0.9476

0.9476

a

explanation: