Which equation can be used to calculate the surface area of the triangular prism net show below?

The net of a rectangular prism. The rectangular sides are 10 centimeters by 13 centimeters, 10 centimeters by 12 centimeters, and 10 centimeters by 5 centimeters. The triangular sides have a base of 5 centimeters and height of 12 centimeters.

[Not drawn to scale]

Surface Area = (one-half) (5) (12) + (5) (10) + (12) (10) + (13) (10)
Surface Area = (one-half) (5) (13) + (one-half) (5) (13) + (13) (10) + (12) (10)
Surface Area = (2) (5) (13) + (5) (10) + (13) (10) + (12) (10)
Surface Area = (one-half) (5) (12) + (one-half) (5) (12) + (5) (10) + (12) (10) + (13) (10)

i'm assuming that it's c.)   volcanoes built the mountains and earthquakes tore them down.

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.