Suppose you have 10 points in the plane with no three collinear. How many di↵erent line segments are formed by joining pairs of of these points? How many di↵erent triangles are formed by these line segments? If A is one of the 10 points, how many of the triangles formed by the line segments have A as a vertex?

a

step-by-step explanation:

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

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step-by-step explanation: