Use the shell method to find the volume of the solid generated by revolving the region bounded by the line yequals=55xplus+66 and the parabola yequals=xsquared2 about the following lines. a. The line xequals=66 b. The line xequals=minus−11 c. The x-axis d. The line yequals=36

a, 72; b, -1/3 c. 30.3

Step-by-step explanation:

y=5x + 6; y= x^2

a. x= 6; 36=5x+6

=> 5x=30; boundary = 0, 6, the volume will be 72 after take integral of parabola through boundary 0, 6

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral