The radius of a cylindrical construction pipe is 2ft. If the pipe is 22ft long, what is it’s volume

276.32 ft³

Step-by-step explanation: Since the cylindrical construction pipe is in the shape of a cylinder, let's start with the formula for the volume of a cylinder.

Here, we're given that our cylinder has a radius of 2 feet and a height of 22 feet so we can plug this information into the formula.

So we have .

Start by simplifying the exponent.

(2 ft)² is 2 feet · 2 feet or 4 ft².

So we have .

Now, (4 ft²) ( 22 ft) is 88 ft³.

So we have 88π ft³.

So the volume of the cylinder is 88π ft³.

Now, remember that the irrational number π is approximately equal to 22/7 or 3.14 so we can estimate the value of the volume by plugging in 3.14 for π.

So we have (88) (3.14) which is equal to 276.32 ft³.

So the value of the volume is approximately equal to 276.32 ft³.

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.