. You've been asked to design a heat (internal combustion) engine with an efficiency of at least 30% on a hot day, when the coolant temperature (TL) is 47°C. Assuming your engine achieves 50% of the ideal Carnot efficiency, what is the minimum temperature TH of the "hot reservoir" (combustion temperature) needed to achieve the desired actual efficiency of 30% or greater?

TH to have 30 % will be 794 degree centigrade

Step-by-step explanation:

efficiency =(TL/TH) *100% , the ideal carnot supposed to be 100 %

hence the minimum temperature of the hot reservior  Th will be half of 794 giving 159 degree centigrade

10 cm

step-by-step explanation:

if the polygon is a rectangle, then the perimeter is x+x+y+y. using the values that you gave, the perimeter is 3+3+2+2=10cm.

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