In Jesus name please help me

Expression J:

–12 ÷ (–3) – 20 ÷ 2 has a value of –6.

Solution:

To find which expression has a value of –6.

Solve these expressions using BODMAS rule.

Expression F: –4 · 2 – (–14)

–4 · 2 – (–14) = –4 · 2 + 14

                      = –8 + 14

                      = 6

Therefore, this is not true.

Expression G: –16 ÷ (–2) – (–2)

First do division by BODMAS rule.

–16 ÷ (–2) – (–2) = 8 – (–2)

                           = 8 + 2

                           = 10

Therefore, this is not true.

Expression H: –2 – (–8) ÷ (–1)

First do division by BODMAS rule.

–2 – (–8) ÷ (–1) = –2 – 8

                         = –10

Therefore, this is not true.

Expression J: –12 ÷ (–3) – 20 ÷ 2

First do division by BODMAS rule.

–12 ÷ (–3) – 20 ÷ 2 = 4 – 20 ÷ 2

                               = 4 – 10

                               = –6

This expression has a value of –6.

Hence it is true.

Therefore –12 ÷ (–3) – 20 ÷ 2 has a value of –6.

how is that middle school

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm