A circle with an arc measure of 160 degrees has an arc length of LaTeX: 20\pi\:cm20 π c m What is the radius of the circle in which the arc sits? Round to the nearest tenth if necessary.

the radius of the circle is 22.5 cm

Step-by-step explanation:

The formula for determining the length of an arc is expressed as

Length of arc = θ/360 × 2πr

Where

θ represents the central angle.

r represents the radius of the circle.

π is a constant whose value is 3.14

From the information given,

Length of arc = 20π cm

θ = 160 degrees

Therefore,

20π = 160/360 × 2 × π × r

20π = 160/360 × 2 × π × r

Dividing both sides of the equation by π, it becomes

20 = 160/360 × 2r

20 × 360 = 160 × 2r = 320r

320r = 7200

r = 7200/320

r = 22.5 cm

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.