Help on number 12 please

Step-by-step explanation:

a=adult ticket

s=student ticket

5a+18s=114

4a+6s=66

multiply by 3

12a+18s=198

12a+18s-5a-18s=198-114

7a=84

a=12

4×12+6s=66

6s=66-48

6s=18

s=3

cost of adult  ticket=12 $

cost of student ticket=3 $

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.