Prove that if m and n are integers and nm is even, then m is even or n is even. What is the best approach here, direct proof, proof by contraposition, or proof by contradiction - why?

Proof by contraposition

Step-by-step explanation:

If m and n both are odd, then mn is also odd.

m and n are integers which is not divisible by 2,

Therefore,

m×n is also not divisible by 2.

Which means mn is odd.

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers