Find the sum of the vectors <−5,2> and <6,9>. Then find the magnitude and direction of the resultant vector. Round angles to the nearest degree and other values to the nearest tenth.

Sum = <1,11>

Magnitude = 11.05

Direction = 84.81

Step-by-step explanation:

Given.

Let Vector A = <-5,2>

Vector B = <6,9>

Sum = A + B

Sum = <-5,2> + <6, 9>

Sum = <-5 + 6, 2 + 9>

Sum = <1,11>

where x = 1 and y = 11

Calculating the magnitude...

Magnitude = √(x² + y²)

Magnitude = √(1² + 11²)

Magnitude = √(1 + 121)

Magnitude = √122

Magnitude = 11.04536101718726

Magnitude = 11.05 --- Approximated

Calculating the vector direction

Direction of a vector is calculated by tan^-1 (y/x)

Direction = tan^-1(11/1)

= tan^-1(11)

= 84.80557109226519

= 84.81° Approximated

395.84

step-by-step explanation:

2πrh+2πr²

2 (pie)(radius)(height)+2(pie)(radius)^2

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92