Pita has 12 coins in her bag.
There are three £1 coins and nine 50p coins.

She takes 3 coins from the bag at random.

work out the probability that she takes exactly £2.50

Probability that she takes exactly £2.50 =  27/220

Number of coins in Pita's bag = 12

Number of £1 coins  =  3

Number of 50p coins  = 9

For Pita to take exactly £2.50 from the bag, it means she has to take two £1 coins and one 50p coin

Total number of coins that Pita has to take from the bag = 3

Number of ways of taking 3 coins out of 12 = 12C3

Number of ways of taking 3 coins out of 12 coins = 220 ways

Number of ways of taking two £1 coins from 3 £1 coins = 3C2

Number of ways of taking two £1 coins from 3 £1 coins = 3 ways

Number of ways of choosing one 50p coin from 9 50p coins = 9C1

Number of ways of choosing one 50p coin from 9 50p coins = 9

Probability that she takes exactly £2.50 = (9x3)/220

Probability that she takes exactly £2.50 =  27/220

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the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

care to share were the trapezoid shown is ?