Mathematics, 28.02.2020 02:17 xbeatdroperzx

Write the equation of the circle that has a center at point K (2, 4) and passes through the point (6,5).
(x + 2)2 + (y + 4)2 = 17
(x + 2)² + (y + 412 = 117
(x - 2)2 + (x-4)² = 17
(x-2)2 + (y - 472 = 117

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Write the equation of the circle that has a center at point K (2, 4) and passes through the point (6,5). (x + 2)2 + (y + 4)2 = 17 (x + 2)² + (y + 412 = 117 (x - 2)2 + (x-4)² = 17 (x-2)2 + (y - 472 = 117

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Another question on Mathematics

Write the equation of the circle that has a center at point K (2, 4) and passes through the point (6,5).
(x + 2)2 + (y + 4)2 = 17
(x + 2)² + (y + 412 = 117
(x - 2)2 + (x-4)² = 17
(x-2)2 + (y - 472 = 117