According to the CDC, the rate of Cesarean births in the United States in 2013 was about 33%. Suppose a random sample of 200 births is selected. Let X be the number of Cesarean births out of all 200 births. What are the values of the parameters for the binomial random variable X?

n=
p=

n = 200

p = 0.33.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

In this problem we have that:

33% of the births are Cesarean, so

Sample of 200 births, which eans that,

6.5

step-by-step explanation:

you said it was in the question

~courtney