Find the perimeter and area of a polygon that has vertices at

H(-3, -2), I(5, -2), J(5, 7), K(-3, 7).

Perimeter of the polygon is 34 units.

Area of the polygon is 72 sq. units

Step-by-step explanation:

To find the perimeter and area, first we have to find the length of the 4 sides, using the distance formula.

H (-3,-2), I(5,-2), J (5,7), K (-3, 7)

Distance formula is given as √((x₂-x₁)² + (y₂-y₁)²)

HI = √ ((5-(-3))² + (-2-(-2))²)

   = √ ((8)² + (0)²) = √8² = 8

IJ = √((5-5)² +(7-(-2))²)

  = √9² = 9

JK = √((-3-5)² +(7-7)²) = √(-8)²

    = 8

KH = √((-3-(-3))² +(-2-7)²) = √(-9)² = 9

Perimeter = 2(l+ b ) = 2(9+8) = 34 units.

Area = l × b = 9 × 8 = 72 sq. units

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

i can you with this question sweetie!

step-by-step explanation: