On a coordinate plane, a curved line with minimum values of (negative 1.56, negative 6) and (3, 0), and a maximum value of (1.2, 2.9), crosses the x-axis at (negative 2.5, 0), (0, 0), and (3, 0), and crosses the y-axis at (0, 0). Which interval for the graphed function has a local minimum of 0? [–3, –2] [–2, 0] [1, 2] [2, 4]

Step-by-step explanation:

On a coordinate plane, a curved line has minimum values of (negative 1.56, negative 6) and (3, 0). This means

1) when , the minimum value of the function is

2) when the minimum value of the function is

Hence, the graphed function has a local minimum of 0, when

Therefore, the interval which contains this value of x is because

answer:

c. the third graph