A^(2)+b^(2)+c^(4)=2020

a=√−c4−b2+2020 or a=−√−c4−b2+2020

b=√−c4−a2+2020 or b=−√−c4−a2+2020

c=cant find it

Step-by-step explanation:

Step 1 for a: Add -c^4 to both sides.

c4+a2+b2+−c4=2020+−c4

a2+b2=−c4+2020

Step 2: Add -b^2 to both sides.

a2+b2+−b2=−c4+2020+−b2

a2=−c4−b2+2020

Step 3: Take square root.

a=√−c4−b2+2020 or a=−√−c4−b2+2020

Step 1 for b: Add -c^4 to both sides.

c4+a2+b2+−c4=2020+−c4

a2+b2=−c4+2020

Step 2: Add -a^2 to both sides.

a2+b2+−a2=−c4+2020+−a2

b2=−c4−a2+2020

Step 3: Take square root.

b=√−c4−a2+2020 or b=−√−c4−a2+2020

d

step-by-step explanation:

i dont understand the question? ?

step-by-step explanation: