Toretto and O’Conner graphed two different quadratic functions in vertex form. Toretto graphed f(x)=(x+3)^2+1 and O’Conner graphed g(x) =-(x-3)^2+1 . Both of them drew the same graph.

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By observing the graph we can say that minimum value of Toretto graph occurs at x=-3

whereas the minimum value of OConner graph occurs at x=3 .

In the given figure the minimum value is at x=3

therefore OConner is correct because the vertex is (3,1)

Hope this helps

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b