The number of days ahead travelers purchase their airline tickets can be modeled by an exponential distribution with the average amount of time equal to 15 days. What is the probability that a traveler will purchase a ticket fewer than ten days in advance?

P(x<10) =0

Step-by-step explanation:

M =1/μ

M= 1/15 =0.066667

X- Exp (0.066667)

Where: X is the random variable for number of days

P (X<x) = 1 - e^-mx

P(X - x) = 1 - e^-0.06666 x10

P(x<10) = 0

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.