Identify the oblique asymptote of f(x) = quantity 3 x squared plus 2x minus 5 over quantity x minus 4 .

y = 0
y = 3x − 10
y = 3x + 14
No oblique asymptote

Step-by-step explanation:

Answer is C

We need to find oblique asymtotes of f(x).

Oblique asymtotes form when degree of numerator is greater than denominator.

First we find the degree of numerator and denominator for f(x)

Degree of f(x) at numerator = 2

Degree of f(x) at denominator = 1

So, one oblique asymtote form.

First we divide  by

Quoetient of the above division would be oblique asymtote.

First we find the degree of numerator and denominator for f(x)

Degree of f(x) at numerator = 2

Degree of f(x) at denominator = 1

So, one oblique asymtote form.

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

i hope this is what you were looking for.

see attached graph