Find the center, vertices, and foci of the ellipse with equation x squared divided by one hundred plus y squared divided by sixty four = 1.

Step-by-step explanation:

The general equation of an ellipse is:

(x − h)²/a² + (y − k)²/b² = 1

where (h, k) is the center.

If a > b, the ellipse is horizontal, so the vertices are at (h ± a, k), and the foci are at (h ± c, k), where c² = a² − b².

If b > a, the ellipse is vertical, so the vertices are at (h, k ± b), and the foci are at (h, k ± c), where c² = b² − a².

x²/100 + y²/64 = 1

The center is (0, 0).

This is a horizontal ellipse, so the vertices are at (-10, 0) and (10, 0).

The distance between the foci and the center is c = √(100 − 64) = 6, so the foci are at (-6, 0) and (6, 0).

Graph: desmos.com/calculator/kd6z9qvhi0

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: