G Based on a poll, 61% of Internet users are more careful about personal information when using a public Wi-Fi hotspot. What is the probability that among four randomly selected Internet users, at least one is more careful about personal information when using a public Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to respond? The probability that at least one of them is careful about personal information is nothing. (Round to three decimal places as needed.) How is the result affected by the additional information that the survey subjects volunteered to respond? A. It is very possible that the result is not valid because not everyone uses public Wi-Fi. B. It is very possible that the result is not valid because the sample may not be representative of the people who use public Wi-Fi. C. The result should not be impacted by this because there is no reason to lie when responding. D. The result should not be impacted by this because volunteers are likely to have the most relevant responses.

P (atleast one is careful) is

1 - 0.012 =0.988

B) It is very possible that the result is not valid because the sample may not be representative of the people who use public Wi-Fi

Step-by-step explanation:

P(not careful) =1 - 0.67 = 0.33

P (4 all not careful) = (0.33)^4 =0.012

P (atleast one is careful) = 1 - 0.012 =0.988

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

a: 1/6, j: 1/4

step-by-step explanation: you are welcome