100 points pls help

George is considering two different investment options. The first option offers 7.4% per year simple interest on the initial deposit. The second option offers a 6.5% interest rate but is compounded quarterly. He may not withdraw any of the money for three years after the initial deposit. Once the minimum 3 years is reached, he can choose to withdraw his money or continue to collect interest. Suppose that George opens one of each type of account and deposits $10,000 into each.

Explanation:

Part A: 7.4% simple interest

Formula:

Calculations:

Part B: 6.5% compounded quaterly

Formula:

Substitute and compute:

Part C: Which investement is better

Over the first three years the first option, 7.4% per year simple interest, is a better investment, because the value of its value is $12,220 - $12,134.0 = $85.94 greater than the second option.

Part D: Recomendation

If George is unsure how long he will keep the money in the account, I would recommend to use the second option, because the compounded interest will overcome the simple interest, since the year 5.  You can show that with a table:

Value of A in $:

Year         Simplet intertest                         Compound interest

1                10,000 + 10,000(0.074)(1)             10,000(1 + 0.0650/4)¹

                 10,740                                           10,666

2              10,000 + 10,000(0.074)(2)             10,000(1 + 0.065/4)²

                11,480                                              11,376

3             10,000 + 10,000(0.074)(3)               10,000(1 + 0.0650/4)³

              12,220                                               12,314

4             10,000 + 10,000(0.074)(4)               10,000(1 + 0.065/4)⁴

              12,960                                               12,942

5             10,000 + 10,000(0.074)(5)                10,000(1 + 0.065/4)⁵

              13,700                                                13,804

idk the answer but just put a

step-by-step explanation:

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: