A piece of iron weighs 250N in air and 200N in a liquid of density 1000kgm^-3 the volume of the iron is?

2.5 x 10-2 ms-8

Step-by-step explanation:

With in the air = 250N

wt. in the liquid = 200N

loss in wt. in the liquid = 250 - 200 = 50N

Wt. the liquid of equal vol. of the iron = 50N

If the density of the liquid is 1000 lgm-3

then the volume of the liquid = (N)/D = V = (25kg)/1000 =0.025m3 = 2.5 x 10-2 m8.

where's the diagrams?

i think its a and d

step-by-step explanation: