The difference of two numbers is nine the larger number is one more than find the larger number

Question:

The difference of two numbers is nine if the larger number is one more than twice the smaller number find a larger number

The larger number is 17

Solution:

Let the smaller number be "a"

Let the larger number be "b"

The difference of two numbers is nine

Therefore,

b - a = 9 eqn 1

larger number is one more than twice the smaller number

Therefore,

b = 1 + 2a eqn 2

Substitute eqn 2 in eqn 1

1 + 2a - a = 9

Substitute a = 8 in eqn 1

b - 8 = 9

b = 9 + 8

Thus the larger number is 17

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

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