Question 9 (Worth 1 points)
(04.03 HC)
Right triangle ABC is on a coordinate plane. Segment AB is on the line y = 2 and is 6 units long. Point C is on the line x = -3. If the area of AABC is 9 square units, then find a
possible y-coordinate of point C.
05
7
8
Points earned on this question: 0

  5

Step-by-step explanation:

The area is half the product of base and height, so that product must be 2×9=18. Since the base is 6, the height must be 18/6 = 3. Two points on line x=-3 are 3 units from y=2. One of them is y=-1; the other is y=5.

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.