How can the function f(x)=x2-6x+8 be rewritten to determine its minimum value?

Minimum value of f(x) = -1.

Step-by-step explanation:

We convert it to vertex form:

x^2 - 6x + 8

= (x - 3)^2 - 9 + 8

= (x - 3)^2 - 1

The minimum value occurs when (x - 3)^2 = 0  because a square has a minimum value of zero ( it cannot be negative for real values of x).

So  the function has a minimum value of -1.

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step-by-step explanation: