I need ONLY number 7 my teacher gave me this packet and i can’t figure that one out

(3x+6)^2

Step-by-step explanation:

the side of the inner square is 3x long

to have the wider square side we must add 3 two times, so 3x + 3 + 3 = 3x+6

to find the area we must square it (3x+6)^2

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7