It says to solve for x but I don’t know how to do it

0 & 3

Step-by-step explanation:

(1/7)x² - (3/7)(x) = 0

Take (1/7)x common

(x/7)(x - 3) = 0

(x/7) = 0 when x = 0

x - 3 = 0 when x = 3

 x = {0, 3}

Step-by-step explanation:

First, clear the denominator.

Then move everything to one side so zero is on the other side (because it is a quadratic equation).  

Next, factor the quadratic equation.

Finally, solve each factor.

65

step-by-step explanation:

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.