Set up a system of equations needed to solve each probler
11. You have 42 coins valued at $3.00. Some of
the coins are dimes and some are quarters. Find the
number of each you have.

This is not a solvable question, since the least amount of money you can have with this combination is $4.20.

Step-by-step explanation:

Let q = quarters

Let d = dimes

Equation: 0.1d + 0.25q = 3.00

Maximum amount of dimes: 0.1d *42 = 4.2d

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !