Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how much was it worth, to the nearest hundred dollars?

Property amount after 11 year is $95,250

Property amount = $75,000

Rate of growth = 2.2% annually

Number of year = 11 year

Property amount after 11 year

A = P[1+r]ⁿ

Property amount after 11 year = 75,000[1+0.022]¹¹

Property amount after 11 year = 75,000[1.022]¹¹

Property amount after 11 year = 75,000[1.27]

Property amount after 11 year = $95,250

link

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

f(x)=2/3x-8, which give g(x) the greatest value.

step-by-step explanation: